解题步骤
解题步骤
① /48→/56：子网位 +8 → 256 块
每块间隔 = 0x100（第 4 组十六进制）
2001:db8:acad::/56
2001:db8:acad:100::/56
2001:db8:acad:200::/56 …
② /56→/64：再 +8 位 → 每站 256 块
2001:db8:acad:100::/64 …Python 验算
Python 验算
python -c "import ipaddress as ipa; n=ipa.ip_network('2001:db8:acad::/48'); print(next(n.subnets(new_prefix=56))); print(next(ipa.ip_network('2001:db8:acad:100::/56').subnets(new_prefix=64)))"
# 2001:db8:acad::/56
# 2001:db8:acad:100::/64